Wednesday, 26 March 2014

Question Example with Solution 1

Heres one of the questions that i saw on Kiasuparents.com P6 PSLE maths topic in the academic section.
The solutions posted there seem to be a little bit complicated so i decided to post a model and conceptual solution to it.

Shop A and Shop B had a total of 10400 packets of flour at first. Both shops sold 3/5 of their packets of flour. Shop B then had 520 more packets of flour than Shop A.
(a) How many packets of flour did Shop B have at first?
(b) Shop B sold each packet of flour at $2.25. How much did Shop B collect?

Since Both shops sold 3/5 and B had 520 more than A in the end,
Your child needs to be able infer that 2/5 of B is 520 more than A. (Sold 3/5, left 2/5)
With the aid of model,


(a)

10 units + 520 + 260 + 260 + 260 = 10400

10 units = 10400 - 1300 = 9100

1 unit = 910

No. of packets B have at first = 5 x 910 + 1300 = 5850

Ans: 5850 packets

(b)

No. of packets sold by B = 3 x 910 + 780 = 3510

Amount collected by B = 3510 x $2.25 = $7897.50

Ans: $7897.50

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